rect intersector check using image (python)

1. make image as numpy
2. add 1 all element for each inside of box
3. check if there is bigger element value than 1

Thank you.

#draw new image

img = np.zeros((int(height), int(width), 1), dtype = "uint8")

#draw new image

img.fill(0)

for i, v in enumerate(box_list):

left = int(v['bbox'][0])

top = int(v['bbox'][1])

right = int(v['bbox'][2])

bottom = int(v['bbox'][3])

img[top:bottom,left:right] += 1

#check overlap

imgv = img.reshape(height*width)

if sum(imgv > 1) > 0:

print('intersector found')